Fortran双精度转换为Python float [英] Fortran double precision converted to Python float

问题描述

我在generation.f90

SUBROUTINE generation(t, prob)
    IMPLICIT NONE

    INTEGER, INTENT(IN) :: t
    REAL(8), INTENT(OUT) :: prob
    INTEGER :: nT2, c

    Do some stuff with t, nT2 and c

    prob = nT2/(DBLE(1.0)*c)
END SUBROUTINE generation

我想在Python中使用它，所以我用f2py

I want to use it in Python, so I wrap it with f2py

f2py -c -m generation generation.f90 --fcompiler=gnu95

然后在ipython我知道

from generation import *
a = generation(10000); type(a)

，我得到float.我检查了生成的C文件testmodule.c

and I get float. I checked the C file testmodule.c generated with

f2py generation.f90 -m test

和prob是double类型.我希望type(a)是numpy.float64.我该怎么办?我对Fortran和f2py还是陌生的.

and prob is type double. I would like type(a) to be numpy.float64. What should I do? I am fairly new to Fortran and f2py.

推荐答案

默认情况下，python中的浮点数是双精度的.较难的问题是获取单精度浮点数，这需要numpy或其他数学软件包.但就您而言，您不应该有任何担忧.

Floats in python are double precision by default. The harder problem is to get a single-precision float, which requires numpy or some other mathematics package. But in your case, you shouldn't have any concerns.

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