将fortran双精度格式读入python [英] Reading fortran double precision format into python

问题描述

我试图读取一个Fortran双精度数字，如1.2345D + 02到python，但是我收到以下错误：

I am trying to read a Fortran double-precision number like 1.2345D+02 into python, but I got the following error:

>>> float('1.2345D+02')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for float(): 1.2345D+02

按照建议在使用D代替E的Python科学符号，我试过numpy但我也得到相同的错误：

By following the advice on Python scientific notation using D instead of E, I tried numpy but I also get the same error:

import numpy
>>> numpy.float("1.2345D+02")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for float(): 1.2345D+02

是否有解决方案在Python中阅读这些双精度数字，而不用将'D'更改为'E'？

Is there a solution in Python to read those double precision numbers without just changing the 'D' to 'E'?

编辑：我替换了字符串上的错误语法。但是我仍然收到错误。

I replaced a bad syntax on the strings. But still I get errors.

推荐答案

float（str.replace（D E））？

请注意，numpy支持fortran符号： numpy.float（1.2345D +02）。

Please note, numpy DOES support fortran notation: numpy.float("1.2345D+02").

你似乎有一些更深层次的目的，可能会说明它会有所帮助。

You seem to have some deeper purpose, perhaps shedding light on it would help.

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