在Pygame，Python 3中设置固定的FPS [英] Setting a fixed FPS in Pygame, Python 3

问题描述

我目前正在使用PyGame(Python 3)制作游戏，并且正在寻找一种使游戏以固定FPS运行的方法.

I'm currently making a game using PyGame (Python 3), and I'm looking for a way to make the game run at a fixed FPS.

大多数游戏都位于一个巨大的while循环内，在此循环中，用户获取输入，渲染精灵等.我的目标是能够设置固定的FPS，使游戏在快速或慢速计算机上以相同的速度运行.

Most of the game is located inside a giant while loop, where the user input is taken, sprites are rendered, etc. every tick. My goal is to be able to set a fixed FPS that will make the game run at the same speed on a fast or slow computer.

我当然可以在pygame中使用时钟模块:

I can, of course, use the clock module in pygame:

clock = pygame.time.Clock()

，然后在每个循环中调用它:

and then call this every loop:

clock.tick(30)

但这会使游戏保持30 FPS的速度.因此，如果将其设置为500 FPS，它可能仍会像以前一样快地运行.我的目标是，如果将其设置为500 FPS，它将以与500 FPS相同的速度运行...

but that will keep the game CAPPED at 30 FPS. So if I set it to 500 FPS it might still run as fast as it did before. My goal is that if I set it to 500 FPS it will run at the same SPEED as it would at 500 FPS...

因此，无论计算机的速度如何，都可以使游戏以固定的FPS运行(或对此产生幻想)，或者通过使用某些跳帧算法至少以相同的速度运行?

So is it possible to make the game run at a fixed FPS (or make an illusion of that), regardless of the speed of the computer - or at least run at the same speed through the use of some frame-skip algorithm?

很抱歉，该措辞令人困惑.

Sorry if that wording was rather confusing.

推荐答案

clock.tick返回自上次调用clock.tick以来的时间.使用该值，并在移动时将所有速度乘以该值. 例子

The clock.tick returns the time since the last call to clock.tick. Use that value and multiply all your speeds with it when you move. Example

dt = clock.tick(60)
player.position.x += player.xSpeed * dt
player.position.y += player.ySpeed * dt

这样，无论您将clock.tick()功能设置为什么，您的播放器都将始终以相同的速度移动.

This way your player will always move at the same speed regardless of what you put into the clock.tick() function.

要记住的重要一点是每帧只调用一次clock.tick().

Important to remember is to only call clock.tick() once per frame.

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