在pygame python3中创建登录系统 [英] Create a log in system in pygame python3
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问题描述
试图让以下 python 代码工作.我想要做的是，对于密码输入框，我希望出现星号，而不是出现输入的字符.
Trying to get the following python code working. What I am trying to do is, for the password input box, instead of the characters inputted appearing, I want asterisks to appear.
我尝试使用其他变量并显示它们，但没有奏效.我已经能够获得存储在变量中的正确数量的星号，但需要帮助用星号覆盖密码框中的文本.
I have tried using other variables and displaying them, but it hasn't worked. I have been able to get the correct number of asterisks stored in a variable, but need help with over-writing the text in the password box with the asterisks.
代码是:
import pygame, pygame.font, pygame.event, pygame.draw, string
from pygame.locals import *
import hashlib, uuid
string=''
hashed_password=''
current_string_p=[]
display_p=[]
symbol='*'
def get_key():
while 1:
event = pygame.event.poll()
if event.type == KEYDOWN:
return event.key
else:
pass
def display_box(screen, message):
"Print a message in a box in the middle of the screen"
fontobject = pygame.font.Font(None,18)
pygame.draw.rect(screen, (0,0,0),
((screen.get_width() / 2) - 100,
(screen.get_height() / 2) - 10,
200,20), 0)
pygame.draw.rect(screen, (255,255,255),
((screen.get_width() / 2) - 102,
(screen.get_height() / 2) - 12,
204,24), 1)
if len(message) != 0:
screen.blit(fontobject.render(message, 1, (255,255,255)),
((screen.get_width() / 2) - 100, (screen.get_height() / 2) - 10))
pygame.display.flip()
def ask(screen, question):
"ask(screen, question) -> answer"
pygame.font.init()
current_string_un = []
display_box(screen, question + ": " + string.join(current_string_un))
while 1:
inkey = get_key()
if inkey == K_BACKSPACE:
current_string_un = current_string_un[0:-1]
elif inkey == K_RETURN:
break
elif inkey == K_LSHIFT or inkey == K_RSHIFT:
inkey=get_key()
if inkey <= 127:
upper_case=inkey-32
current_string_un.append(chr(upper_case))
elif inkey <= 127:
current_string_un.append(chr(inkey))
display_box(screen, question + ": " + string.join(current_string_un))
return string.join(current_string_un)
#password
global display_p
global current_string_p
current_string_p = []
display_p=[]
pro=''.join(display_p)
display_box(screen, question + ": " + pro)
while 1:
inkey = get_key()
if inkey == K_BACKSPACE:
current_string_p = current_string_p[0:-1]
display_p = display_p[0:-1]
elif inkey == K_RETURN:
## print(display_p))
break
elif inkey == K_LSHIFT or inkey == K_RSHIFT:
inkey=get_key()
if inkey <= 127:
upper_case=inkey-32
for character in current_string_p:
display_p.append(symbol)
pro=''.join(display_p)
display_box.blit(screen, question + ": " + pro)
current_string_p.append(chr(upper_case))
elif inkey <= 127:
for character in current_string_p:
display_p.append(symbol)
pro=''.join(display_p)
display_box.blit(screen, question + ": " + pro)
current_string_p.append(chr(inkey))
## return string.join(display_p)
return display_p
## return string.join(current_string_p)
def strong_password(password):
#a strong password will have a capital letter, a lowercase letter and a number
passloop = 1
hasdigit = 0
uppercase = 0
#checks each character to check password meets requirements
for character in password:
if character.isdigit():
hasdigit += 1
else:
pass
if character == character.upper():
if character.isdigit():
pass
else:
uppercase += 1
else:
pass
if hasdigit > 0 and uppercase > 0:
passloop = 2
print('strong password')
else:
passloop = 1
print('weak password')
def main():
global display_p
display_p=[]
screen = pygame.display.set_mode((320,240))
print (ask(screen, "Username") + " was entered")
x = ask(screen, "Password")
for character in x:
display_p.append(symbol)
pro=''.join(display_p)
print (x + " was entered")
print(pro)
#check password security
strong_password(x)
#hash password
salt = "5gz"
hashing_password = x+salt
h = hashlib.md5(hashing_password.encode())
print(h.hexdigest())
if __name__ == '__main__':
main()
我认为问题出在这一部分:
I think the issue is with this section:
#password
global display_p
global current_string_p
current_string_p = []
display_p=[]
pro=''.join(display_p)
display_box(screen, question + ": " + pro)
while 1:
inkey = get_key()
if inkey == K_BACKSPACE:
current_string_p = current_string_p[0:-1]
display_p = display_p[0:-1]
elif inkey == K_RETURN:
## print(display_p))
break
elif inkey == K_LSHIFT or inkey == K_RSHIFT:
inkey=get_key()
if inkey <= 127:
upper_case=inkey-32
for character in current_string_p:
display_p.append(symbol)
pro=''.join(display_p)
display_box.blit(screen, question + ": " + pro)
current_string_p.append(chr(upper_case))
elif inkey <= 127:
for character in current_string_p:
display_p.append(symbol)
pro=''.join(display_p)
display_box.blit(screen, question + ": " + pro)
current_string_p.append(chr(inkey))
## return string.join(display_p)
return display_p
## return string.join(current_string_p)
推荐答案
你可以渲染 '*' 倍于你的密码长度.
You could just render '*' times the length of your password.
import pygame as pg
pg.init()
FONT = pg.font.Font(None, 42)
def main():
screen = pg.display.set_mode((640, 480))
clock = pg.time.Clock()
password = ''
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
elif event.type == pg.KEYDOWN:
if event.key == pg.K_RETURN:
# Do something with the password and reset it.
print(password) # I just print it to see if it works.
password = ''
else: # Add the character to the password string.
password += event.unicode
screen.fill((30, 30, 30))
# Render the asterisks and blit them.
password_surface = FONT.render('*'*len(password), True, (70, 200, 150))
screen.blit(password_surface, (30, 30))
pg.display.flip()
clock.tick(30)
if __name__ == '__main__':
main()
pg.quit()
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