Nodejs分页 [英] Nodejs Pagination

问题描述

我想对Nodejs和Mongoose进行分页.我可以限制帖子，但无法处理前端到后端的连接.

I want to make a pagination with Nodejs and Mongoose. I can limit the posts but I couldn't handle the connection of front-end to back-end.

这是app.js:

app.get('/', function (req, res) {
  var perPage = 2
  var page = req.params.page || 1

  Metin
  .find({})
  .skip((perPage * page) - perPage)
  .limit(perPage)
  .exec(function(err, metins) {
      Metin.count().exec(function(err, count) {
          if (err) return next(err)
          res.render('index', {
              metins: metins,
              current: page,
              pages: Math.ceil(count / perPage)
          })
      })
  })
});

这是我的index.pug

extends layout

block content
  body
    br 
    br
    br
    .container
      ul.list-group
        each metin, i in metins
          li.list-group-item
            a(href="/metin/" + metin._id)= metin.baslik

我想添加可以传递到相关分页网页的按钮.你能帮我吗?

I want to add buttons that can pass to related paginated webpage. Can you please help me?

此行下方的内容可以解决吗?

Something like below this line can be solution ?

a(href='?page=' + pages)= length.pages.

推荐答案

您可以使用 迭代器可遍历pages变量，从而为您的每个页面添加一个数字.并且根据current变量有条件地显示/隐藏上一个/下一个链接.如果您没有大量的页面，这应该可以工作:

You can use while iterator to loop over the pages variable to make a number for each of your pages. And conditionally show/hide Previous/Next links based on current variable. This should work if you don't have a large amount of pages:

ul
  if current > 1
    li
      a(href=`?page=${parseInt(current) - 1}`) Previous
  - var i = 1
  while i <= pages
    li
      a(href=`?page=${i}`)= i++
  if current < pages
    li
      a(href=`?page=${parseInt(current) + 1}`) Next

此外，请参见 查看全文