PHP警告:ftp_fput():无法打开该文件:是该目录中的 [英] PHP Warning: ftp_fput(): Can't open that file: Is a directory in
问题描述
我正在尝试将文件上传到FTP.
I'm trying to upload a file to FTP.
这是我的代码:
$connect = ftp_connect('ftp.my-server.fr');
$login = ftp_login($connect, 'username', 'pass');
$remote_file = '/' . $date;
$local_file = fopen('C:/MAMP/htdocs/mysite/myfolder/' . $hour .'.mp3', 'r');
ftp_chdir($connect, '/'.$date);
if (ftp_fput($connect, $remote_file, $local_file, FTP_ASCII)) {
echo "The file $local_file has been loaded";
} else {
echo "Error while uploading file " . $local_file;
}
我遇到错误:
PHP警告:ftp_fput():无法打开该文件:是第26行上C:\ MAMP \ htdocs \ mysite \ index.php中的目录
PHP Warning: ftp_fput(): Can't open that file: Is a directory in C:\MAMP\htdocs\mysite\index.php on line 26
我不明白,因为路径是文件.当我在浏览器中粘贴$local_file
URL时,声音正在播放.
I don't understand because the path is the file. When I paste $local_file
URL in my browser the sound is playing.
推荐答案
您的$local_file
可以,但是您的$remote_file
是目录(您将'/' . $date
用于ftp_chdir
),并且它必须是文件的路径(将被创建)
Your $local_file
is OK, but your $remote_file
is a directory (you use '/' . $date
for ftp_chdir
), and it need to be a path to a file (that will be created)
您可以使用basename
复制与本地文件相同的文件名:
You can copy the same filename than the local file with basename
:
$remote_dir = '/' . $date;
$local_file = fopen('C:/MAMP/htdocs/mysite/myfolder/' . $hour .'.mp3', 'r');
ftp_chdir($connect, $remote_dir);
$remote_file = $remote_dir . '/' . basename($local_file) ;
if (ftp_fput($connect, $remote_file, $local_file, FTP_ASCII)) {
echo "The file $local_file has been loaded";
} else {
echo "Error while uploading file " . $local_file;
}
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