无法从 python 目录中打开文件 [英] Can't Open files from a directory in python

问题描述

我写了一个小模块，它首先找到目录中的所有文件，然后合并它们.但是，我在从目录中打开这些文件时遇到了问题.我确保我的文件和目录名称是正确的，并且文件实际上在目录中.

I have written a small module that first finds all the files in the directory, and merge them. But, I'm having the problem with opening these files from a directory. I made sure that my files and directory names are correct, and files are actually in the directory.

下面是代码..

 seqdir = "results"
 outfile = "test.txt"

 for filename in os.listdir(seqdir):
     in_file = open(filename,'r') 

下面是错误..

     in_file = open(filename,'r')     
     IOError: [Errno 2] No such file or directory: 'hen1-1-rep1.txt'

推荐答案

listdir 只返回文件名:https://docs.python.org/2/library/os.html#os.listdir 您需要完整路径才能打开文件.在打开它之前还要检查以确保它是一个文件.示例代码如下.

listdir returns just the file names: https://docs.python.org/2/library/os.html#os.listdir You need the fullpath to open the file. Also check to make sure it is a file before you open it. Sample code below.

for filename  in os.listdir(seqdir):
    fullPath = os.path.join(seqdir, filename)
    if os.path.isfile(fullPath):
        in_file = open(fullPath,'r')
        #do you other stuff

但是对于文件，最好使用 with 关键字打开.即使有异常，它也会为您处理关闭.请参阅 https://docs.python.org/2/教程/inputoutput.html#methods-of-file-objects 细节和例子

However for files it is better to open using the with keyword. It handles closing for you even when there are exceptions. See https://docs.python.org/2/tutorial/inputoutput.html#methods-of-file-objects for details and an example

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