"sizeof(函数名)"返回什么? [英] What does 'sizeof (function name)' return?

问题描述

示例代码:

int main(void)
{
    printf ("size = %d\n", sizeof(main));
}

应用于函数名称(例如main)的返回值sizeof是什么?

What is the returned value sizeof applied to a function name, for example main?

推荐答案

C标准禁止使用-用gcc -pedantic编译时，会产生invalid application of ‘sizeof’ to a function type警告.

C standard forbids it - when compiled with gcc -pedantic, it produces invalid application of ‘sizeof’ to a function type warning.

但是gcc编译它并为sizeof(main)返回1，它不是函数指针的大小.

However gcc compiles it and returns 1 for sizeof(main), and it is not a size of function pointer.

它似乎与编译器有关.

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