如何在归一化输出中返回两个归一化值的和 [英] How to return sum of two normalized values in a normalized output

问题描述

我需要一个函数，使a和b都在[0..1]范围内，并加上a和b并返回在[0..1]范围内的输出，当总和大于1时，它将换为零类似于mod函数.

I need a function that takes a and b both in [0..1] range, and adds a and b and returns the output in [0..1] range, when the sum is above 1 it wraps to zero like mod function.

我尝试了这个，但是不起作用:

I tried this but it doesn't work:

function shift(a, b) {
  return (a + b) % 1;
}

例如，对于a = 1和b = 0，它返回0，但我希望它返回1.

For example for a = 1 and b = 0, it returns 0 but I want it to return 1.

推荐答案

我认为您能做的最好的事情是:

I think the best you can do is something like:

function normalize(a, b) {
  let r = (a + b);
  return r === 1 ? 1 : r % 1;
}

当总和恰好为0时将返回0，而当总和恰好为1时将返回1.其他值换行"回到0 ... 1范围内.

This will return 0 when the sum is exactly 0, and 1 when the sum is exactly 1. Other values "wrap" back into the 0 ... 1 range.

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