删除列中特定字符之后的字符 [英] Remove characters after a specific character in column

问题描述

我有一个文件:

chr12   121164863   +   NM_000017
chr17   7126029-7126037 +   NM_000018
chr11   108004589-108004593 +   NM_000019
chr12   52306964-52306968   +   NM_000020

我想要做的是删除此所需输出的第2列中-之后的字符:

What I want to do is to remove the characters after the - in column 2 for this desired output:

chr12   121164863   +   NM_000017
chr17   7126029 +   NM_000018
chr11   108004589   +   NM_000019
chr12   52306964    +   NM_000020 

关于如何实现此目标的任何建议?我在想awk或sed，但是它们变得很快.

Any suggestions on how to accomplish this? I was thinking awk or sed, but they have gotten complicated fast.

推荐答案

使用awk，您可以

$ awk '{$2+=0}1' file
chr12 121164863 + NM_000017
chr17 7126029 + NM_000018
chr11 108004589 + NM_000019
chr12 52306964 + NM_000020

，或者如果您希望它适用于非数字数据:

or if you want it to work for non-numeric data:

awk '{split($2,a,/-/);$2=a[1]}1' file

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