打印两个图案(BEGIN和END)之间的最小线条集，包括这两个图案的线条 [英] Print the smallest set of lines between two patterns (BEGIN and END) including the lines of these two patterns

问题描述

aaa
Any--END--Pattern
bbb
ANY--BEGIN--PATTERN
ccc                   # do not print
ANY--BEGIN--PATTERN   # print 1
ddd                   # print 2
Any--END--Pattern     # print 3
eee
fff
ANY--BEGIN--PATTERN   # print 4
ggg                   # print 5
Any--END--Pattern     # print 6
hhh                   # print 7
Any--END--Pattern     # print 8
iii                   # do not print
ANY--BEGIN--PATTERN
jjj

想要的输出

ANY--BEGIN--PATTERN   # print 1
ddd                   # print 2
Any--END--Pattern     # print 3
ANY--BEGIN--PATTERN   # print 4
ggg                   # print 5
Any--END--Pattern     # print 6
hhh                   # print 7
Any--END--Pattern     # print 8

注释

• 从最新的ANY--BEGIN--PATTERN开始打印，在当前的Any--END--Pattern之前.
• 如果没有ANY--BEGIN--PATTERN满足，则打印直到最后一个Any--END--Pattern.

Notes

• Print from the latest ANY--BEGIN--PATTERN before the current Any--END--Pattern.
• Print until the last Any--END--Pattern if no ANY--BEGIN--PATTERN meet.
• 单行打印两个图案之间的所有行 [perl]
• 如何在两种模式之间选择行? [awk/sed/grep]
• 仅在两个模式之间的行打印中删除了第一个匹配项
• 如何在两个标记模式之间选择可能会因awk/sed多次出现的行
• 使用awk和可变正则表达式提取两个模式之间的线
• 如何在两个标记模式之间选择可能会因awk/sed多次出现的行
• ...
• One-liner to print all lines between two patterns [perl]
• How to select lines between two patterns? [awk/sed/grep]
• awk print only lines between two patterns removing first match
• How to select lines between two marker patterns which may occur multiple times with awk/sed
• Extract lines between two patterns with awk and a variable regex
• How to select lines between two marker patterns which may occur multiple times with awk/sed
• ...

我从这些问题中测得的答案将打印ccc行和/或iii行...或者不打印具有BEGIN和END模式的行.我的几次尝试都具有这些相同的缺点和缺陷.

The answers I have tested from these questions print the line ccc and/or the line iii... or do not print the lines having the BEGIN and END patterns. My several attempts have these same drawbacks and defects.

我们可以编写一个十行的脚本，但是我敢肯定有一个优雅的单行命令可以解决此问题，但是我找不到它.因此，我认为这可能是一个很好的SO问题；-)

We could write a ten lines script, but I am sure there is an elegant one-line command solving this issue but I cannot find it. Therefore I think this could be a good SO question ;-)

我想知道从sed，awk，perl或类似Unix的系统上易于使用的任何其他工具中使用什么技巧.请使用以下命令提供一个简短的命令行: bash ， grep ， sed ， awk ， perl 或您认为的其他任何工具...

I wonder what are the tricks to use from sed, awk, perl or any other tool available easy on our Unix-like systems. Please provide a tiny command line using : bash, grep, sed, awk, perl or any other tool you think...

只需在 Sundeep 的注释中强调非常简单的命令行即可，该注释通过反转输入文件来简化问题:

Just to underline the pretty simple command line from Sundeep's comment that simplifies the problem by reversing the input file:

tac input.txt | sed -n '/END/,/BEGIN/p' | tac

但是此命令行也会打印开头
^{(这种情况对于其他有类似问题的用户可能不会发生)}

But this command line also prints the beginning
^{(this case may not happen for other users looking a similar issue)}

aaa
Any--END--Pattern
ANY--BEGIN--PATTERN   # print 1
ddd                   # print 2
Any--END--Pattern     # print 3
ANY--BEGIN--PATTERN   # print 4
ggg                   # print 5
Any--END--Pattern     # print 6
hhh                   # print 7
Any--END--Pattern     # print 8

_{(此答案用于推荐答案}

awk进行救援！

$ awk '/BEGIN/{c=0; b=1} 
              {a[c++]=$0} 
      b&&/END/{for(i=0;i<c;i++) print a[i]; delete a; c=0}' file

ANY--BEGIN--PATTERN   # print 1
ddd                   # print 2
Any--END--Pattern     # print 3
ANY--BEGIN--PATTERN   # print 4
ggg                   # print 5
Any--END--Pattern     # print 6
hhh                   # print 7
Any--END--Pattern     # print 8

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