使用 sed 删除两个模式(不包括)之间的线条 [英] removing lines between two patterns (not inclusive) with sed

问题描述

好的

我知道这是一个微不足道的问题，但是:如何从两个已知模式/单词之间的文件中删除行:

I know that this is trivial question but: How can i remove lines from files that are between two known patterns/words:

模式1
垃圾
模式2

pattern1
garbage
pattern2

获得:

模式1
模式2

有没有人知道学习 sed 的好(简单写！)资源​​??有很多清晰的例子吗?

And does anyone known good(simple written!) resources for studying sed?? With many clear examples?

推荐答案

sed -n '/pattern1/{p; :a; N; /pattern2/!ba; s/.*
//}; p' inputfile

说明:

/pattern1/{         # if pattern1 is found
    p               # print it
    :a              # loop
        N           # and accumulate lines
    /pattern2/!ba   # until pattern2 is found
    s/.*
//        # delete the part before pattern2
}
p                   # print the line (it's either pattern2 or it's outside the block)

某些版本的 sed 必须用勺子喂食:

Some versions of sed have to be spoon-fed:

sed -n -e '/pattern1/{' -e 'p' -e ':a' -e 'N' -e '/pattern2/!ba' -e 's/.*
//' -e '}' -e 'p' inputfile

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