SED 删除两个模式之间的特定行? [英] SED delete specific lines between two patterns?

问题描述

我正在尝试使用 sed 过滤 *.ics 文件.*.ics 文件如下所示:

I am trying to filter an *.ics file using sed. The *.ics file looks like this:

[...]

BEGIN:VEVENT
UID:0xfoo
SUMMARY:foo
DTSTART:20131212T090000
DTEND:20131212T100000
SEQUENCE:0
DTSTAMP:20131212T100000
LOCATION:foo
CATEGORIES:foo
DESCRIPTION:foo
CLASS:PUBLIC
END:VEVENT

[...]

我想删除开头的行，例如使用 UID 或 SEQUENCE，但前提是它们介于 BEGIN:VEVENT 和 END:VEVENT

I want to delete lines starting e.g. with UID or SEQUENCE, but only if they are between BEGIN:VEVENT and END:VEVENT

我尝试删除这些行:

sed '/^BEGIN:VEVENT/,/^END:VEVENT/ /^UID/d'

但它只会返回一个错误，比如unknown command '/'

But it will only return an error saying something like unknown command '/'

如何删除这些行?

谢谢！

推荐答案

试试这一行:

 sed '/^BEGIN:VEVENT/,/^END:VEVENT/{/^(UID|SEQUENCE)/d}' file

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