SED删除两个模式之间的特定行？ [英] SED delete specific lines between two patterns?

问题描述

我正在尝试使用 sed 过滤 *。ics 文件。 *。ics 文件如下所示：

I am trying to filter an *.ics file using sed. The *.ics file looks like this:

[...]

BEGIN:VEVENT
UID:0xfoo
SUMMARY:foo
DTSTART:20131212T090000
DTEND:20131212T100000
SEQUENCE:0
DTSTAMP:20131212T100000
LOCATION:foo
CATEGORIES:foo
DESCRIPTION:foo
CLASS:PUBLIC
END:VEVENT

[...]

我想删除以具有 UID 或 SEQUENCE 的条件，但前提是它们在之间 BEGIN：VEVENT 和 END：VEVENT

I want to delete lines starting e.g. with UID or SEQUENCE, but only if they are between BEGIN:VEVENT and END:VEVENT

我尝试使用以下方式删除这些行：

I tried to delete these lines with:

sed '/^BEGIN:VEVENT/,/^END:VEVENT/ /^UID/d'

但是它只会返回一条错误消息，例如 unknown command'/'

But it will only return an error saying something like unknown command '/'

如何删除这些行？

谢谢！

推荐答案

尝试以下行：

 sed '/^BEGIN:VEVENT/,/^END:VEVENT/{/^\(UID\|SEQUENCE\)/d}' file

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