C ++:整数常量对其类型而言太大 [英] C++ : integer constant is too large for its type
问题描述
我需要粗暴训练一年.编译器不断抛出此错误:
I need to bruteforce a year for an exercise. The compiler keep throwing this error:
bruteforceJS12.cpp:8:28:警告:整数常量对于其类型而言太大(默认情况下启用)
bruteforceJS12.cpp:8:28: warning: integer constant is too large for its type [enabled by default]
我的代码是:
#include <iostream>
using namespace std;
int main(){
unsigned long long year(0);
unsigned long long result(318338237039211050000);
unsigned long long pass(1337);
while (pass != result)
{
for (unsigned long long i = 1; i<= year; i++)
{
pass += year * i * year;
}
cout << "pass not cracked with year = " << year << endl;
++year;
}
cout << "pass cracked with year = " << year << endl;
}
请注意,我已经尝试使用unsigned long long result(318338237039211050000ULL);
Note that I already tried with unsigned long long result(318338237039211050000ULL);
我正在使用gcc版本4.8.1
I'm using gcc version 4.8.1
以下是使用InfInt库的更正版本 http://code.google.com/p/infint /
Here is the corrected version using InfInt library http://code.google.com/p/infint/
#include <iostream>
#include "InfInt.h"
using namespace std;
int main(){
InfInt year = "113";
InfInt result = "318338237039211050000";
InfInt pass= "1337";
while (pass != result)
{
for (InfInt i = 1; i<= year; i++)
{
pass += year * i * year;
}
cout << "year = " << year << " pass = " << pass << endl;
++year;
}
cout << "pass cracked with year = " << year << endl;
}
推荐答案
A quick way to figure out the numeric limits on your system would be to use std::numeric_limits. The output on my system when I run the following code:
#include <iostream>
#include <limits>
int main()
{
std::cout << "ull\t"
<< std::numeric_limits<unsigned long long>::lowest() << '\t'
<< std::numeric_limits<unsigned long long>::max() << std::endl ;
}
是:
ull 0 18446744073709551615
我们可以看到最大值肯定小于您的字面值:
we can see the max value is definitely smaller than your literal value:
18446744073709551615
318338237039211050000
因此,对于 unsigned long long 类型,您的整数文字太大.
So your integer literal is just too large for unsigned long long type.
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