GNU gdb如何显示源文件名和符号行 [英] GNU gdb how to show source file name and lines of a symbol

问题描述

使用GNU gdb调试c进程时.

when use GNU gdb to debug a c process.

list命令将打印行，但不会告诉我文件名.

list command will print the lines but not telling me the file name.

设置断点可以显示我想要的所有行和文件信息，但是我不想设置断点，而必须禁用或删除它.

set breakpoints can display all the line and file info I want but I don't want to set a breakpoint and have to disable or delete it.

(gdb) b oyss_funtion
Breakpoint 13 at 0x8049130: file main.c, line 119.

是否存在gdb命令或设置可以向我显示函数(符号)的文件行信息，而无需在那里设置断点?

Is there a gdb command or settings can show me the file line info of a function(symbol) without setting a breakpoint there?

推荐答案

使用info line命令.

info line oyss_function

例如，假设文件test.c包含:

#include <stdio.h>

int main(void)
{
    printf("\n");
    return 0;
}

然后，在GDB中调用info line main会得到:

Then, invoking info line main in GDB gets:

(gdb) info line main
Line 4 of "test.c" starts at address 0x400498 <main> and ends at 0x40049c <main+4>.

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