在gdb调试器中标识符号的源文件名 [英] Identify source file name for a symbol in gdb debugger

问题描述

我正在Ubuntu 18.04上的 gdb 中调试基于多个C ++共享库的应用程序，而
想查找源代码（或至少找到它的名称）共享库或C ++名称空间）称为 TRUE 的符号。

I am debugging an application based on multiple C++ shared libraries in gdb on Ubuntu 18.04 and want to find the source code (or at least the name of the shared library or C++ namespace) of a symbol called TRUE.

所有代码均已使用 -g3 -O0 -Wall 。

编辑： 仅可用于共享库的调试符号，并且使用 -g3 -O0 -Wall 编译应用程序代码。

I have "only" the debug symbols available for shared libraries and the application code is compiled with -g3 -O0 -Wall.

这是我对 gdb 中的符号的了解：

Here is what I know about the symbol in gdb:

(gdb) ptype TRUE
type = enum {FALSE, TRUE}
(gdb) whatis TRUE
type = enum {...}
(gdb) info line TRUE
(gdb) 

我如何找出谁定义了枚举我的 TRUE 符号`？

How can I find out who defined the enum of my TRUE symbol`?

有类似的问题，但答案没有提供预期的输出（但为空，请参见上面的日志）： https://stackoverflow.com/a/20771062

There is a similar question but the answer does not give the expected output (but empty, see log above): https://stackoverflow.com/a/20771062

编辑：我又走了一步（但对于这样一种常见的文件名，仍然缺少完整路径）：

I am one step further (but still the full path is missing for such a common kind of file name):

(gdb) python print(gdb.lookup_symbol("TRUE")[0].symtab)
api.cpp

推荐答案

我终于找到了！ Python是解决方案，与纯本地的 gdb 命令相比，Python中的 gdb 对象确实提供了更详细的信息：

I have found it finally! Python is the solution, the gdb object within Python does offer more detailed information than the pure native gdb commands:

(gdb) python print(gdb.lookup_symbol("TRUE")[0].symtab.fullname())
/media/devmount/dev/R/Rcpp/src/api.cpp

有关详细信息，请参阅文档： https：/ /sourceware.org/gdb/download/onlinedocs/gdb/Symbol-Tables-In-Python.html#Symbol-Tables-In-Python

For details see the documentation: https://sourceware.org/gdb/download/onlinedocs/gdb/Symbol-Tables-In-Python.html#Symbol-Tables-In-Python

编辑：我已经找到了 gdb 命令，但是对于我来说似乎不起作用：

I have found gdb command for that but it seems not to work in my case:

(gdb) set print symbol-filename on
(gdb) show print symbol-filename
Printing of source filename and line number with <symbol> is on.
(gdb) ptype TRUE
type = enum {FALSE, TRUE}

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