为什么C#中的这种隐式类型转换失败? [英] Why does this implicit type conversion in C# fail?
问题描述
假设我上了以下课程:
class Wrapped<T> : IDisposable
{
public Wrapped(T obj) { /* ... */ }
public static implicit operator Wrapped<T>(T obj)
{
return new Wrapped<T>(obj);
}
public void Dispose() { /* ... */ }
}
如您所见,它为T
→提供了隐式类型转换运算符. Wrapped<T>
.最终,我希望能够如下使用此类:
As you can see, it provides an implicit type conversion operator for T
→ Wrapped<T>
. Ultimately, I would like to be able to use this class as follows:
interface IX { /* ... */ }
class X : IX { /* ... */ }
...
IX plainIX = new X();
using (Wrapped<IX> wrappedIX = plainIX)
{
/* ... */
}
问题:
但是,上述using
子句中的类型转换失败.虽然可以直接将new X()
分配给wrappedIX
,但是不允许我将任何类型为IX
的东西分配给它.编译器将抱怨以下错误:
Problem:
However, the type conversion in the above using
clause fails. While I can assign a new X()
directly to wrappedIX
, I am not allowed to assign anything of type IX
to it. The compiler will complain with the following error:
编译器错误CS0266:无法将类型'IX'隐式转换为'Wrapped< IX>'.存在明确的onversion(您是否缺少演员表?)
我不明白这一点.这是什么问题?
I don't understand this. What's the problem here?
推荐答案
我相信是因为IX
是接口.编译器认为,也许IX
类型的值可能已经从Wrapped<IX>
派生了(即使Wrapped<T>
是密封的),所以它不使用转换.
I believe it's because IX
is an interface. The compiler thinks that maybe a value of type IX
could already be derived from Wrapped<IX>
(even if Wrapped<T>
is sealed) so it doesn't use the conversion.
在C#3.0规范的6.4.3和6.4.4节中,详细信息非常复杂.基本上因为IX
是接口,所以没有任何类型包含",这意味着6.4.4中的后续步骤失败.
The details are quite complicated, in sections 6.4.3 and 6.4.4 of the C# 3.0 spec. Basically because IX
is an interface, it's not "encompassed by" any types, which means a later step in 6.4.4 fails.
我建议您使用此方法创建非通用类型Wrapped
:
I suggest you create a non-generic type Wrapped
with this method:
public static Wrapped<T> Of<T>(T item)
{
return new Wrapped<T>(item);
}
然后您可以编写:
using (Wrapped<IX> wrappedIX = Wrapped.Of(plainIX))
出于各种原因,基本转换可能会有些棘手-IMO通常更易于理解简单的方法.
Basically conversions can be a bit tricky for various reasons - simple methods are generally easier to understand, IMO.
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