Kotlin使用子类型覆盖乐趣 [英] Kotlin override fun with subtype
问题描述
我在继承包含基本类型的方法/乐趣的接口时遇到麻烦,我想在实现它的类中将其重写为子类型.
Im having trouble inheriting an interface containing a method/fun of a base type, that i would like to override as a subtype in the class implementing it.
到目前为止,我已经有了界面
So far i have the interface
interface IModel {
fun convert(dataModel: BaseDataModel)
}
以及实现它的类:
class SettingsModel: IModel {
override fun convert(dataModel: BaseDataModel) {
// Conversion of models here
}
}
我也有SettingsDataModel,它是:
And i also have the SettingsDataModel which is:
class SettingsDataModel: BaseDataModel() {
}
我想要实现的是针对实现IModel的每个类/模型,能够获得特定的DataModel,例如:
What i'm trying to achieve is for every class/model implementing IModel, being able to get the specific DataModel, like:
class SettingsModel: IModel {
override fun convert(dataModel: SettingsDataModel) {
// Conversion of models here
}
}
无需强制转换.我想我做不到,因为它修改了乐趣的签名,使其不是真正的替代.我尝试使用泛型和泛型约束,但是没有运气:
without needing to cast it. I guess i cant because it modifies the signature of the fun making it not a real override. I tried using generics and generic constraints but no luck:
interface IModel {
fun <T :BaseDataModel>convert(dataModel: T)
}
,但不起作用.有什么解决办法吗?
but its not working. Any work around for this?
推荐答案
如何?
interface IModel<T : BaseDataModel> {
fun convert(dataModel: T)
}
class SettingsModel: IModel<SettingsDataModel> {
override fun convert(dataModel: SettingsDataModel) {
// Conversion of models here
}
}
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