是否有可能在git for-each-ref中过滤掉合并的分支? [英] Is it possible to filter out merged branches in git for-each-ref?

问题描述

基本上我想要类似于git branch -a --no-merged的东西，但是我也想列出标签，并且我不需要空格或remotes/origin/HEAD -> origin/master

Basically I want something similar to git branch -a --no-merged but I'd also like to list tags and I don't need the spaces before or stuff like remotes/origin/HEAD -> origin/master

我可以使用for-each-ref进行此操作吗?还是最好只从git branch中剥离不需要的内容，然后分别获取标签?

Can I do this with for-each-ref or is it better to just strip the stuff I don't want from git branch then get the tags separately?

推荐答案

git for-each-ref和类似的git show-ref不能自行决定一个引用是否是另一个引用的祖先，但您始终可以构建管道，例如:

git for-each-ref and the similar git show-ref do not have the ability to decide whether one reference is an ancestor of another on its own, but you can always build a pipeline, e.g.:

uninteresting=master # or some other way to identify ones to discard
git for-each-ref |
while read sha1 reftype refname; do
    if git merge-base --is-ancestor $refname $uninteresting; then
        # $refname / $sha1 "is merged", or is exactly equal
        ... do whatever you like here ...
    else
        # there is no ancestry path from $uninteresting back to $refname
        ... do whatever else you like here ...
    fi
done

请注意，git merge-base --is-ancestor master master始终为true.如果您不希望将等于但名称不同"视为合并"(并且这取决于它是分支还是其他引用类型?)，您将在此处需要一些额外的代码，但是我怀疑您确实希望等于表示合并".

Note that git merge-base --is-ancestor master master is always true. If you don't want "equal but name differs" considered to be "merged" (and does this depend on whether it's a branch or some other ref type?) you will need some extra code here, but I suspect you do want "equal means merged".

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