在同一3D图形上根据散点和png绘制3D曲面 [英] Plotting 3D surface from scatter points and a png on the same 3D graph

问题描述

我需要在同一张图上绘制基于散点数据和2D图像(.png)的3D表面，该2D图像位于图上确定的位置，以比较两者的数据.到目前为止，我设法分别完成了这两项工作(绘制图像并制作表面).

I need to plot on the same graph a 3D surface based on a scatter points data and a 2D image (.png), positioned in a determined location on the graph to compare the data from both. So far I managed to do both separately (plotting the image and making the surface).

但是，当我尝试将两个脚本放到同一脚本上时，我收到一条错误消息(未实现颜色列的网格化")，该错误消息是由于创建与该表面冲突的命令(dgrid3d)而发生的图片.我想知道如何避免此错误.

However, when I try to bring both together on the same script, I get an error message ("Gridding of the color Column is not implemented") which occurs due to the command that creates the surface (dgrid3d) that conflicts with the image. I want to know how can I avoid this error.

预先感谢

*编辑

分散点采用xyz格式:

The scatter points are on xyz format:

-100.000000 -25.000000 -4.122210

-100.000000 -20.000000 -4.933388

-100.000000 -15.000000 -7.902138

-100.000000 -10.000000 -7.902138

图片是普通的png.

我正在使用的脚本是:

set hidden3d
set samples 100
set isosamples 100
unset surface
set pm3d
set dgrid3d

 splot '444_0.dat' u 1:2:3 \
 splot 'test.png' \
 binary filetype=png flipy rotate=-90d center = (4,-25,5.7) perp=(0,1,0) with rgbimage

由于我之前指出的错误而无法正常工作

which doesnt work due to the error I pointed before

推荐答案

错误消息表明问题出在dgrid3d.您可能能够解决的一种方法是将表面绘制到桌子上:

The error message suggests that the problem is with dgrid3d. One way that you might be able to get around that is to plot the surface to a table:

set terminal push #Save current terminal settings
set terminal unknown #dummy terminal
set table "surface.dat"
set dgrid3d
splot 'surface_points.dat' using ...
unset dgrid3d
unset table
set term pop #reset current terminal settings
set output "MyPlot.extension"

#commands to plot image and `surface.dat` together.

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