如何将Go字符串文字代码转换为其值? [英] How to transform Go string literal code to its value?

问题描述

我在Go中的语法树中走来走去，试图找到对某个特定函数的所有调用，然后获取其字符串参数(这是文件名，应为字符串文字，而不是其他任何标识符).我已经成功完成了，现在我有了ast.BasicLit节点和Kind == token.STRING，但是它的值是Go代码，而不是它应该具有的字符串值.

I'm walking around syntax tree in Go, trying to find all calls to some particular function and then get its string argument (it's a file name, and should be string literal, not any other identifier). I'm succeeded with this, and now I have ast.BasicLit node with Kind == token.STRING, but its value is Go code, not a value of the string that it should have.

我发现了一个问题，该问题回答了如何进行反向转换-从字符串到代表它的代码:

I found question that answers how to do reverse transformation - from string to go code it represents: golang: given a string, output an equivalent golang string literal

但是我想要相反的东西-类似于eval函数(但仅适用于Go字符串文字).

But I want the opposite - something like eval function (but just for Go string literals).

推荐答案

您可以使用 进行转换(取消报价).

You can use the strconv.Unquote() to do the conversion (unquoting).

您应该注意的一件事是，strconv.Unquote()只能取消对引号中的字符串的引用(例如，以引号char "或反引号char `开头和结尾)，因此您必须手动如果没有引号，请附加.

One thing you should be aware of is that strconv.Unquote() can only unquote strings that are in quotes (e.g. start and end with a quote char " or a back quote char `), so you have to manually append that if it's not in quotes.

示例:

fmt.Println(strconv.Unquote("Hi"))       // Error: invalid syntax
fmt.Println(strconv.Unquote(`Hi`))       // Error: invalid syntax
fmt.Println(strconv.Unquote(`"Hi"`))     // Prints "Hi"
fmt.Println(strconv.Unquote(`"Hi\x21"`)) // Prints "Hi!"

// This will print 2 lines:
fmt.Println(strconv.Unquote(`"First line\nSecondline"`))

输出(在游乐场上尝试):

 invalid syntax
 invalid syntax
Hi <nil>
Hi! <nil>
First line
Secondline <nil>

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