如何添加XML属性JAXB注释类XmlElementWrapper？ [英] How can I add xml attributes to jaxb annotated class XmlElementWrapper?

问题描述

我有一个XmlElementWrapper注解类，如：

I have a class with a XmlElementWrapper annotation like:

...

  @XmlElementWrapper(name="myList")
    @XmlElements({
    @XmlElement(name="myElement") }
    )
    private List<SomeType> someList = new LinkedList();

...
这code产生XML像

... This code produces XML like

<myList>
  <myElement> </myElement>
  <myElement> </myElement>
  <myElement> </myElement>
</myList>

到目前为止好。

但现在我需要的属性添加到列表标记获取XML像

But now I need to add attributes to the list tag to get XML like

<myList number="2">
  <myElement> </myElement>
  <myElement> </myElement>
  <myElement> </myElement>
</myList>

有没有一种聪明的方式实现这一目标而无需创建一个包含重新presents列表中的一个新的类？

Is there a 'smart way to achieve this without creating a new class that contains represents the list?

推荐答案

我得到了你的问题更好的解决方案。

I got a better solution for your question.

有关让XML的Java对象，请使用以下code：

For making Xml Java object, use the following code:

import java.util.*;
import javax.xml.bind.annotation.*;

@XmlRootElement(name="myList")
public class Root {

    private String number;
    private List<String> someList;

    @XmlAttribute(name="number")
    public String getNumber() {
        return number;
    }

    public void setNumber(String number) {
        this.number = number;
    }

    @XmlElement(name="myElement")
    public List<String> getSomeList() {
        return someList;
    }

    public void setSomeList(List<String> someList) {
        this.someList = someList;
    } 

    public Root(String numValue,List<String> someListValue) {
        this();
        this.number = numValue;
        this.someList = someListValue;  
    }

    /**
     * 
     */
    public Root() {
        // TODO Auto-generated constructor stub
    }

}

要使用JAXB运行上面的code，使用以下命令：

To run the above code using JAXB, use the following:

   import java.util.ArrayList;
import java.util.List;

import javax.xml.bind.*;

public class Demo {

        public static void main(String[] args) throws Exception {
            List<String> arg = new ArrayList<String>();
            arg.add("FOO");
            arg.add("BAR");
            Root root = new Root("123", arg);

            JAXBContext jc = JAXBContext.newInstance(Root.class);
            Marshaller marshaller = jc.createMarshaller();
            marshaller.marshal(root, System.out);
        }
}

这将产生下面的XML作为输出：

This will produce the following XML as the output:

    <?xml version="1.0" encoding="UTF-8" standalone="yes"?>
    <myList number="123">
        <myElement>FOO</myElement>
        <myElement>BAR</myElement>
    </myList>

我觉得这是比较有帮助你。

I think this is more helpful you.

谢谢..

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