如何在pyparsing中匹配括号/括号 [英] How to match parentheses / brackets in pyparsing

问题描述

我有一个语法标记，指定为:

I have a grammar token specified as:

list_value = Suppress(oneOf("[ (")) + Group(
    delimitedList(string_value | int_value))("list") + Suppress(oneOf("] )"))

但是，这显然允许(foo, bar]

如何强制列表的开头和结尾字符必须匹配?

How do I enforce that the lists opening and closing characters must match?

推荐答案

您在两个规则之间做出选择:一个用于括号，一个用于方括号.感谢您提出pyparsing.我喜欢.我对您的问题的回答是:

You make a list a choice between two rules: one for parentheses and one for square brackets. Thanks for bringing up pyparsing. I like it. My answer for your question is:

delim_value = Group(delimitedList(string_value | int_value))("list")
list_value = Or( (Suppress("[") + delim_value + Suppress("]"),
                  Suppress("(") + delim_value + Suppress(")")) )

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