在Graphviz中排列等级 [英] Align Ranks in Graphviz

问题描述

这是对方法的后续问题可以对graphviz点进行严格的反向排名吗?，但是要容易一些.该图是人为设计的，但演示了该问题:

This is a follow-up question to How can I achieve strict reverse ranking of graphviz dot?, but a little easier. This graph is contrived, but demonstrates the problem:

digraph nfa {
    A -> B
    B -> C
    C -> D
    D -> E
    A -> F
    F -> E
}

节点B和F具有相同的等级，但是它们不在同一等级上显示.如何做到这一点?

Nodes B and F are the same rank, but they are not displayed at the same rank. How can achieve this?

推荐答案

我将子图与rank = same一起使用，并手动计算等级并将其分组在所述子图中.

I used subgraphs with rank = same, and manually computed the ranks and grouped them in said subgraphs.

digraph {
    { rank = same; A }
    { rank = same; B; F }
    { rank = same; C }
    { rank = same; D }
    { rank = same; E }
    A -> B
    B -> C
    C -> D
    D -> E
    A -> F
    F -> E
}

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