如何使用Groovy将soapui中的请求复制到文件夹? [英] How to copy a request in soapui to a folder using groovy?

问题描述

我是Groovy的新手，我希望有一个soap请求，其中包含我要在运行TestCase时复制到具有特定名称的文件夹中的文件.我的测试用例将被创建；首先禁用肥皂请求，然后执行将运行并复制肥皂的常规操作.你能请教吗?

I am new in groovy and I want to have soap request which contains file which I want to be copy to a folder with a specific name when I am running my TestCase. My testcase will be created; first soap request disable and the groovy that will run and copy the soap. Can you please advise?

推荐答案

def cur_Time = Calendar.getInstance(TimeZone.getTimeZone('IST')).format("EEE, dd MMM yyyy HH-mm-ss z")

new File("C:\\Users\\SHILPA\\Desktop\\soapUIxls\\RequestPayload"+cur_Time+".doc").write(context.rawRequest)  

这将有助于通过传递的动态值捕获请求有效负载.

It will help to capture request payload with dynamic values passed.

因此您可以在soapUIlog中看到请求和响应负载

So you can see request and response payloads in soapUIlog

log.info(context.response)
log.info(context.rawRequest)

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