在Ruby中按身份分组 [英] Group by identity in Ruby

问题描述

Ruby的 group_by() 方法是根据数组元素的标识(或更确切地说是self)对数组进行分组?

How does Ruby's group_by() method group an array by the identity (or rather self) of its elements?

a = 'abccac'.chars
# => ["a", "b", "c", "c", "a", "c"]

a.group_by(&:???)
# should produce...
# { "a" => ["a", "a"],
#   "b" => ["b"],
#   "c" => ["c", "c", "c"] }

推荐答案

在较新的Ruby(2.2+?)中，

In a newer Ruby (2.2+?),

a.group_by(&:itself)

在较老的版本中，您仍然需要执行a.group_by { |x| x }

In an older one, you still need to do a.group_by { |x| x }

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