通过同一连接访问多个gRPC服务 [英] Access multiple gRPC services over the same connection

问题描述

我正在运行在localhost:6000上侦听的grpc服务器，公开了2个grpc服务:RegisterSubscriberServiceServer和RegisterDropperServiceServer.由于这两个服务都可以通过localhost:6000进行访问，因此我只想从存根中拨打该地址.

I am running a grpc server listening on localhost:6000, exposing 2 grpc services: RegisterSubscriberServiceServer and RegisterDropperServiceServer. Since both of these services are reachable from localhost:6000, I'd like to only dial this address from the stub.

服务器如下:

func main() {
    grpcServer := grpc.NewServer()
    pb.RegisterSubscriberServiceServer(grpcServer, &subscriberServer{})
    pb.RegisterDropperServiceServer(grpcServer, &dropperServer{})

    l, err := net.Listen("tcp", ":6000")
    if err != nil {
        log.Fatalf("failed to listen: %v", err)
    }

    log.Println("Listening on tcp://localhost:6000")
    grpcServer.Serve(l)
}

为什么每个grpc服务都需要拨不同的套接字?

Why do I need to dial a different socket for each grpc service?

type DropperRPC struct {
    conn      *grpc.ClientConn
    client pb.DropperServiceClient
    chunkSize int
}

type SubscriberRPC struct {
    conn      *grpc.ClientConn
    client pb.SubscriberServiceClient
    chunkSize int
}

func NewSubscriber() (c SubscriberRPC, err error) {
    c.conn, err = grpc.Dial("localhost:6000", grpc.WithInsecure())
    if err != nil {
        log.Fatal(err)
    }
    c.client = pb.NewSubscriberServiceClient(c.conn)
    return
}

func NewDropper() (c DropperRPC, err error) {
    c.conn, err = grpc.Dial("localhost:6000", grpc.WithInsecure())
    if err != nil {
        log.Fatal(err)
    }
    c.client = pb.NewDropperServiceClient(c.conn)
    return
}

由于代码基本上是重复的，以适应每种服务，所以我不能只使用Interface来减少代码吗?

And since the code is basically duplicated to accommodate each service, can't I just use an Interface to reduce the code?

func main() {
    c1, err := NewSubscriber()
    if err != nil {
        log.Fatal(err)
    }

    c2, err := NewDropper()
    if err != nil {
        log.Fatal(err)
    }

    cc1 := &c1
    cc2 := &c2
}

，然后使用此Interface为每个服务实现客户端grpc功能，而不是为每个服务创建新的struct.我已经找到 cmux ，但是必须有一种无需使用外部库即可完成此操作的方法.

And then use this Interface to implement the client side grpc functions for each service, instead of creating a new struct for each service. I have found cmux , but there must be a way to do this without using external libraries.

推荐答案

为什么每个grpc服务都需要拨一个不同的插座?

Why do I need to dial a different socket for each grpc service?

你不知道.您可以创建一个grpc.ClientConn并将其传递给多个pb.New*Client()函数，它们将共享相同的连接.

You don't. You can create one grpc.ClientConn and pass it to multiple pb.New*Client() functions, and they will share the same connection(s).

func main() {
    cc, err := grpc.Dial("localhost:6000", grpc.WithInsecure())
    if err != nil {
        log.Fatal(err)
    }
    c1 := pb.NewSubscriberServiceClient(cc)
    c2 := pb.NewDropperServiceClient(cc)
}

然后使用此接口为每个服务实现客户端grpc函数，而不是为每个服务创建新的结构

And then use this Interface to implement the client side grpc functions for each service, instead of creating a new struct for each service

pb.go文件中生成的代码完成了执行RPC所需的一切.除非您有特殊的逻辑要在每次执行呼叫时自动发生，否则您不必实现任何客户端功能.

The generated code in the pb.go file does everything you need to perform RPCs. You shouldn't have to implement anything client-side unless you have special logic you want to happen automatically every time you perform a call.

如果这两个服务具有唯一的方法名称，则可以将它们放在相同的结构中，这样就不必为了一个较小的方便而单独使用它们了:

If the two services have unique method names, you could put them into the same struct so you don't have to use them separately, as a minor convenience:

type SubscriberDropper struct {
    pb.SubscriberServiceClient
    pb.DropperServiceClient
}

func main() {
    // ... as above ...
    sd := &SubscriberDropper{c1, c2}
}

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