在R中，使用gsub删除除句点以外的所有标点符号 [英] in R, use gsub to remove all punctuation except period

问题描述

我是R的新手，希望您能帮助我.

I am new to R so I hope you can help me.

我想使用gsub删除除点号和减号外的所有标点符号，以便可以在数据中保留小数点和负号.

I want to use gsub to remove all punctuation except for periods and minus signs so I can keep decimal points and negative symbols in my data.

示例

我的数据框z具有以下数据:

My data frame z has the following data:

     [,1] [,2]   
[1,] "1"  "6"    
[2,] "2@"  "7.235"
[3,] "3"  "8"    
[4,] "4"  "$9"   
[5,] "£5" "-10" 

我想使用gsub("[[:punct:]]", "", z)删除标点符号.

I want to use gsub("[[:punct:]]", "", z) to remove the punctuation.

当前输出

> gsub("[[:punct:]]", "", z)
     [,1] [,2]  
[1,] "1"  "6"   
[2,] "2"  "7235"
[3,] "3"  "8"   
[4,] "4"  "9"   
[5,] "5"  "10" 

但是，我想保留-"符号和."符号.签名.

I would like, however, to keep the "-" sign and the "." sign.

所需的输出

 PSEUDO CODE:  
> gsub("[[:punct:]]", "", z, except(".", "-") )
         [,1] [,2]  
    [1,] "1"  "6"   
    [2,] "2"  "7.235"
    [3,] "3"  "8"   
    [4,] "4"  "9"   
    [5,] "5"  "-10" 

有什么想法可以使某些字符免于gsub()函数吗?

Any ideas how I can make some characters exempt from the gsub() function?

推荐答案

您可以放回一些类似的匹配项:

You can put back some matches like this:

 sub("([.-])|[[:punct:]]", "\\1", as.matrix(z))
     X..1. X..2.  
[1,] "1"   "6"    
[2,] "2"   "7.235"
[3,] "3"   "8"    
[4,] "4"   "9"    
[5,] "5"   "-10"  

在这里，我保留.和-.

我想，下一步是将您的结果强制为数字矩阵，因此在这里，我将两个步骤结合起来:

And I guess , the next step is to coerce you result to a numeric matrix, SO here I combine the 2 steps like this:

matrix(as.numeric(sub("([.-])|[[:punct:]]", "\\1", as.matrix(z))),ncol=2)
   [,1]    [,2]
[1,]    1   6.000
[2,]    2   7.235
[3,]    3   8.000
[4,]    4   9.000
[5,]    5 -10.000

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