Python 正则表达式，删除除 unicode 字符串的连字符以外的所有标点符号 [英] Python regex, remove all punctuation except hyphen for unicode string

问题描述

我有这个用于从正则表达式字符串中删除所有标点符号的代码:

I have this code for removing all punctuation from a regex string:

import regex as re    
re.sub(ur"\p{P}+", "", txt)

如何更改它以允许使用连字符?如果你能解释一下你是如何做到的，那就太好了.我明白了，如果我错了，请纠正我，P 在标点符号后面加上任何内容.

How would I change it to allow hyphens? If you could explain how you did it, that would be great. I understand that here, correct me if I'm wrong, P with anything after it is punctuation.

推荐答案

[^\P{P}-]+

\P 是 \p 的补充 - 不是标点符号.所以这匹配任何not(不是标点符号或破折号) - 导致除破折号之外的所有标点符号.

\P is the complementary of \p - not punctuation. So this matches anything that is not (not punctuation or a dash) - resulting in all punctuation except dashes.

示例:http://www.rubular.com/r/JsdNM3nFJ3

如果你想要一个简单的方式，另一种选择是 \p{P}(?<!-):匹配所有标点符号，然后检查它不是破折号(使用负面回顾).
工作示例:http://www.rubular.com/r/5G62iSYTdk

If you want a non-convoluted way, an alternative is \p{P}(?<!-): match all punctuation, and then check it wasn't a dash (using negative lookbehind).
Working example: http://www.rubular.com/r/5G62iSYTdk

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