将字符串值替换为R中查找列表中的值 [英] Replace the string value with value in the find list in R

问题描述

我有一个数据集，其中包含

I have a dataset that has a column like

   string<-c('lib1_Rstudio_case1','lib2_Rstudio_case1and2','lib5_python_notthe correct_language','lib3_Jupyter_really_good','lib1_spyder_nice','lib1_R_the_core')
   replacement<-c('Rstudio','Jupyter','spyder','R')

我要替换与替换中的值匹配的字符串值id.我现在正在使用以下代码

I want to replace the string value id they match the value in replacement. I am using the following code right now

gsub(paste(replacement, collapse = "|"), replacement = replacement, x = string)

这是我用来查找案例的另一段代码

This in another piece of code which i am using to find the cases

string[grepl(paste(replacement, collapse='|'), string, ignore.case=TRUE)]

我想更新我发现的那些 我希望输出像

I want to update the ones that I find I want the output to be like

Rstudio,Rstudio,'',Jupyter,spyder,R

我不想通过硬编码来做到这一点.我想写一个可扩展的代码.

I don't want to do it by hard coding it. I want to write a code that is scalable.

我们非常感谢您的帮助

提前感谢

推荐答案

这是我使用的另一个简单代码.不需要regex函数.感谢帮助

This another simple code I used. That doesn't need the regex function.Thanks for the help

string<-c('lib1_Rstudio_case1','lib2_Rstudio_case1and2','lib5_python_notthe correct_language','lib3_Jupyter_really_good','lib1_spyder_nice','lib1_R_the_core')
replacement<-c('R','Jupyter','spyder','Rstudio')
replaced=string
replaced=''


for (i in 1:length(replacement))
{
  replaced[which(grepl(replacement[i],string))]=replacement[i]
}
replaced[is.na(replaced)]=''

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