将Python转换为Lua:替换列表中的字符串字符 [英] Translate Python to Lua: replace a string character in a list

问题描述

我正在学习Lua，我对python有一定的了解，我想像在python中一样替换字符串中的字符，但是我并没有幸运地找到确切的翻译功能.

I'm learning Lua and I have some knowledge of python and I want to replace a character in a string just like in python but I didn't get lucky to find the exact translation functions.

我想在Lua中做这个

l = ["#01","#02", "#03"]
print(l)

for i in range(len(l)):
    l[i]=l[i].replace("#","")
    #print (i)

print (l)

推荐答案

首先在Python中，您将使用列表推导:

Firstly in Python you would use a list comprehension:

>>> l = ["#01", "#02", "#03", "04"]
>>> l = [s.replace('#', '') for s in l]
>>> print(l)
['01', '02', '03', '04']

如果您确实需要更新列表:

If you really need to update the list in place:

>>> l[:] = [s.replace('#', '') for s in l]

在Lua中，您可以使用 for 遍历列表/数组/表使用 gsub 替换子字符串:

In Lua you can iterate over the list/array/table with for and use gsub to replace the substrings:

> l = {"#01", "#02", "#03", "04"}
> for k, v in pairs(l) do print(k, v) end
1   #01
2   #02
3   #03
4   04

> for k in next,l do l[k] = l[k]:gsub("#", "") end
> for k, v in pairs(l) do print(k, v) end
1   01
2   02
3   03
4   04

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