在一行中包含所有功能的module.exports [英] module.exports that include all functions in a single line

问题描述

这是对

我想包含一个外部js文件，其中包含一个node.js应用程序的常用功能.

I would like to include an external js file that contains common functions for a node.js app.

从在Node.js中，如何包含"

From one of the answers in In Node.js, how do I "include" functions from my other files?, this can be done by

// tools.js
// ========
module.exports = {
  foo: function () {
    // whatever
  },
  bar: function () {
    // whatever
  }
};

var zemba = function () {
}

导出每个功能很不方便.是否可以单线导出所有功能?看起来像这样；

It is inconvenient to export each and every function. Is it possible to have a one-liner that exports all functions? Something that looks like this;

module.exports = 'all functions';

这种方式非常方便.如果以后忘记导出某些功能，它的错误也较少.

It is so much more convenient this way. It is also less buggy in case one forgets to export certain functions later.

如果不是单线的，是否有更简单的替代方法使编码更方便?我只想方便地包含一个由通用功能组成的外部js文件.类似于C/C ++中的include <stdio.h>.

If not a one-liner, are there simpler alternatives that make coding more convenient? I just want to include an external js file made up of common functions conveniently. Something like include <stdio.h> in C/C++.

推荐答案

您可以先编写所有函数声明，然后将它们导出到对象中:

You can write all your function declarations first and then export them in an object:

function bar() {
   //bar
}

function foo() {
   //foo
}

module.exports = {
    foo: foo,
    bar: bar
};

虽然没有神奇的一线工具，但您需要显式导出要公开的功能.

There's no magical one-liner though, you need to explicitly export the functions you want to be public.

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