hist.default(xa)中的错误:"x"必须为数字 [英] Error in hist.default(xa) : 'x' must be numeric

问题描述

我是一名完全R的初学者，并且正在尝试做一些非常基础的事情-制作我从Excel导入的两个向量的直方图.

I'm a complete R beginner, and am trying to do something pretty basic - make histograms of two vectors I imported from Excel.

向量是xa和xb.我尝试了hist(xa)，并收到以下错误:

The vectors are xa and xb. I tried hist(xa), and get the following error:

Error in hist.default(xa) : 'x' must be numeric

因此，我进行了一些搜索，并尝试使用as.numeric(xa)对此进行补救，并得到:

So I did some searching, and tried to remedy this using as.numeric(xa), and got:

Error: (list) object cannot be coerced to type 'double'

所以我尝试了as.list函数，但是它将我的向量变成了矩阵.不太确定发生了什么.向量中的数字都是介于-2到+10之间的所有4位数字.任何帮助将不胜感激！

So I tried the as.list function, but it turned my vector into a matrix. Not really sure what's going on. The numbers in the vectors are all 4 digits between about -2 and +10. Any help would be greatly appreciated!

推荐答案

您可以尝试以下方法...不能保证，因为您没有给出有效的示例:

Here's something you can try... no guarantees, since you have not given a working example:

newXa <- sapply(xa, as.numeric)
hist(newXa)

应该做的是看看'x'的结构

What should be done is to look at the structure of 'x'

str(x)

然后，如果'xa'是指x [['a']]的方式，您将执行以下操作:

Then if 'xa' is how you are referring to x[['a']] you would do this:

hist( x[['a']] )

如果str(x)显示"a"列是一个因素，那么使用此列可能会获得更大的成功:

And if str(x) showed that the "a" column were a factor, one might have more success with this:

 hist( as.numeric(as.character(x[['a']]))  )

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