在Watson Assistant中有条件地从题外话中返回 [英] Conditionally return from digression in watson assistant

问题描述

我一直在阅读文档，找不到Watson Assistant的此问题的答案.

I have been reading through the documentation and cannot find the answer to this question for Watson Assistant.

我有点题外话，有时候我只想返回对话框中的上一个地方.

I have a digression that I only sometimes want to return back to the previous place in the dialog.

具体来说，在用户输入题外话之后，如果用户回答是"，那么我不希望题外话返回，但是如果用户回答否"，那么我确实希望题外话返回到先前的地方

Specifically, after the user enters the digression, if the user responds "Yes" then I do not want the digression to return back, but if the user responds "No" then I do want the digression to return to the previous place.

有没有办法做到这一点?也许通过手动编辑JSON以某种方式覆盖指令以在某些情况下从题外话返回?

Is there a way to do this? Perhaps by manually editing the JSON to somehow override the directive to return from the digression in some cases?

下面是问题的示意图:

对话框流

推荐答案

有一个函数<? clearDialogStack() ?>，当调用该函数时，它将擦除对话框中设置的所有题外话，因此该对话框不会从题外返回.因此，只需在不希望WA返回的节点中调用此函数.

There is a function <? clearDialogStack() ?> that when called it will erase all the digressions that are set in dialog and hence the dialog will not return from digression. So just call this function in a node where you don't want WA to return.

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