StringIndexOutOfBoundsException字符串索引超出范围错误 [英] StringIndexOutOfBoundsException String index out of range error

问题描述

输入整数后输入字符串"s"时出现此错误.

I am getting this error when I enter the String "s" after entring an integer.

Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 0
    at java.lang.String.charAt(Unknown Source)
    at oneB.change(oneB.java:4)
    at oneB.main(oneB.java:26)

下面是代码:(请注意，代码仍然完整，我已经输入了一些打印语句以进行检查)

Following is the code: (Please note that the code is still complete and I have entered some print statements for checking)

import java.util.Scanner;
public class oneB {
    public static String change(int n, String s, String t) {

        if (s.charAt(0) == 'R') {
            return onetwo(s);
        }
        return s;
    }
    private static String onetwo(String one) {
        int c = one.indexOf('C');
        System.out.print(c);
        char[] columnarray = new char[one.length() - c - 1];
        for (int i = c + 1; i < one.length(); i++) {
            columnarray[i] = one.charAt(i);
        }
        int columnno = Integer.parseInt(new String(columnarray));
        System.out.print(columnno);
        return one;

    }
    public static void main(String[] args) {
        Scanner in = new Scanner(System. in );
        int n = in .nextInt();
        String s = in .nextLine();
        String t = in .nextLine();
        System.out.print(change(n, s, t));
    }

}

推荐答案

调用in.nextInt()将结束符留在流中，因此以下对in.nextLine()的调用将导致一个空字符串.然后，将空字符串传递给引用其第一个字符的函数，从而获得异常.

The call in.nextInt() leaves the endline character in the stream, so the following call to in.nextLine() results in an empty string. Then you pass an empty string to a function that references its first character and thus you get the exception.

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