Java - “字符串索引超出范围”例外 [英] Java - "String index out of range" exception

问题描述

我只为练习编写了这个小函数，但抛出异常（String index out of range：29）并且我不知道为什么......

I wrote this little function just for practice, but an exception ("String index out of range: 29") is thrown and I don't know why...

（我知道这不是编写此函数的最佳方法，我可以使用正则表达式。）

(I know this isn't the best way to write this function and can I use regular expressions.)

这是代码：

public String retString(String x) 
{
    int j=0;
    int i=0;
    StringBuffer y = new StringBuffer(x);

try
{


    while ( y.charAt(i) != '\0' )
    {
        if (y.charAt(i) != ' ')
        {
            y.setCharAt(j, y.charAt(i));
            i++;
            j++;
        }
        else
        {
            y.setCharAt(j, y.charAt(i));
            i++;
            j++;
            while (y.charAt(i) == ' ')
                i++;
        }           
    }
    y.setCharAt(j,'\0');



}
finally 
{

    System.out.println("lalalalololo " );
}

    return y.toString();


}

推荐答案

<你正在翻译另一种语言的代码吗？您正在循环遍历字符串，直到您到达空字符（\0），但Java通常不会在字符串中使用这些字符。在C中，这可行，但在你的情况下你应该尝试

Are you translating this code from another language? You are looping through the string until you reach a null character ("\0"), but Java doesn't conventionally use these in strings. In C, this would work, but in your case you should try

i < y.length()

而不是

y.charAt(i) != '\0'

< hr>

此外，

---

Additionally, the

 y.setCharAt(j,'\0')

在代码末尾不会调整字符串大小，如果这是你期望的那样。您应该尝试

at the end of your code will not resize the string, if that is what you are expecting. You should instead try

y.setLength(j)

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