查找图是否有周期 [英] Find whether graph has a cycle

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本文介绍了查找图是否有周期的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想确定是否可以使用SQL在Hierarchical或Chain数据中找到循环.

I want to find out whether it is possible to find cycles in Hierarchical or Chain data with SQL.

例如我有以下架构: http://sqlfiddle.com/#!3/27269

E.g. I have following schema: http://sqlfiddle.com/#!3/27269

create table node (
  id INTEGER
 );

create table edges (
   id INTEGER,
   node_a INTEGER,
   node_b INTEGER
);

create table graph (
  id INTEGER,
  edge_id INTEGER);

INSERT INTO node VALUES (1) , (2), (3), (4);
INSERT INTO edges VALUES (1, 1, 2), (2, 2, 3) , (3, 3, 4) , (4, 4, 1);
-- first graph [id = 1] with cycle (1 -> 2 -> 3 -> 4 -> 1)
INSERT INTO graph VALUES (1, 1), (1, 2), (1, 3), (1, 4); 
-- second graph [id =2] without cycle (1 -> 2 -> 3)
INSERT INTO graph VALUES (2, 1), (2, 2), (2, 3); 

graph表中具有相同ID的记录属于一个图.

In graph table records with same ID belong to one graph.

我需要一个查询,该查询将返回至少有一个周期的所有图的ID.

I need a query that will return IDs of all graphs that have at least one cycle.

因此,例如上述查询应返回1,这是第一张图的ID;

So for example above query should return 1, which is the id of the first graph;

推荐答案

首先,我假设这是一个有向图.如果无向图只包含一条边,则其周期很短.

First, I assume this is a directed graph. An undirected graph has a trivial cycle if it contains a single edge.

递归CTE唯一棘手的部分是在遇到周期时停止-因此您不会得到无限递归.

The only tricky part to the recursive CTE is stopping when you've hit a cycle -- so you don't get infinite recursion.

尝试一下:

with cte as (
      select e.object_a, e.object_b, iscycle = 0
      from edges e
      union all
      select cte.object_a, e.object_b,
             (case when cte.object_a = e.object_b then 1 else 0 end) as iscycle
      from cte join
           edges e
           on cte.object_b = e.object_a
      where iscycle = 0
     )
select max(iscycle)
from cte;

这篇关于查找图是否有周期的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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