派生类参数如何在Python中工作? [英] How does derived class arguments work in Python?

问题描述

我很难理解Python中的一件事，我已经使用Python进行了很长时间的编码，但是今天有些事情令我震惊，我一直难以理解

I am having difficulty understanding one thing in Python.I have been coding in Python from a very long time but there's is something that just struck me today which i struggle to understand

所以情况就这样

我有一个混音和一个视图

I have a mixin and a view

class Mixin:
    def get_session(self,request,*args,**kwargs):
        print(self) #should be the instance passed
        print(request) #should be the request object passed but it's also an instance

class View:
     def get(self,request,*args,**kwargs):
         self.get_session(self,request,*args,*kwargs)
         pass

为什么请求参数是类视图的实例，应该是请求.请帮助我阐明这些概念.

Why is the request argument the instance of the Class View, It should be request.Please help me clarify these concepts.

推荐答案

您正在显式传递self作为get_session的第一个参数.这意味着它进入了request参数.

You're passing self explicitly as the first argument of get_session. That means it goes into the request parameter.

self.get_session(self,request,*args,*kwargs)
  ^               ^        ^^^^^^^^^^
(self)        (request)    (the rest)

我想你的意思是:

self.get_session(request, *args, **kwargs)

这篇关于派生类参数如何在Python中工作?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！