在初始化脚本中切换用户? [英] Switch user in a init script?

问题描述

这是我在Ubuntu工作站上拥有的Init脚本.我需要以root用户以外的其他用户身份运行命令，但是我只是无法理解应该如何执行. sudo -u或su newuser似乎都不起作用.

Here's my Init script which I have at my Ubuntu workstation. I need to run a command as another user than root, but I just can't get my head around how it should be done. Neither sudo -u or su newuser seems to work.

脚本:

respawn
console none

start on runlevel [2345]
stop on runlevel [06]

script
  su "anotherUser" -c ./myCommand
end script

推荐答案

我使用这个:

su -l $MUSER -c "myCommand args..."

更新:由于对此答案很感兴趣，因此我在这里解释了使用它的方式.

Update: Since there is interest in this answer, I explain the way I use it here.

我们以普通linux用户而不是root用户的身份运行服务器.用户名包含三个部分:

We run servers as normal linux users, not root. The username contains three parts:

服务，客户，阶段

这样，我们可以在一个Linux操作系统中为多个客户运行多种服务.

This way we can run several services for several customers in one linux OS.

示例:foo_bar_p客户"bar"的服务"foo"，"p"表示生产

Example: foo_bar_p Service "foo" of customer "bar" and "p" means production

这是初始化脚本的一部分.初始化脚本可以以root或foo_bar_p用户身份执行:

Here is the part of the init script. The init script can be executed as root or as foo_bar_p user:

# /etc/init.d/foo_bar_p-celeryd
# scriptname contains linux username  
SCRIPT_NAME=`basename "$0"`
SYSTEM=${SCRIPT_NAME%*-celeryd}

U=`id -nu`

if [ ! $U == $SYSTEM ]; then
    if [ $U == "root" ]; then
        # use "-l (login)" to delete the environment variables of the calling shell.
        exec su -l $SYSTEM -c "$0 $@"
    fi
    echo "Script must be run from $SYSTEM or root. You are '$U'"
    rc_exit 1
fi

# OK, now I am foo_bar_p
cd
. $HOME/.bashrc
....

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