从整数中删除尾随零的更好方法 [英] Better way to remove trailing zeros from an integer

问题描述

我是一个没有经验的程序员.我正在尝试从整数中删除尾随零，这是我在python中设置的项目的结果.

I'm an inexperienced programmer. I'm trying to remove trailing zeros from a whole number, an integer, for a project I've set myself in python.

我已经做到了，但是必须有比我炮制的怪兽更好的方法！

I have managed to do this but there must be a better way than the monstrosity I have concocted!

def removeZeros(number):
    return int(str(int(str(number)[::-1]))[::-1])

基本上，我是将整数转换为字符串，然后将其反转，然后将其转换为整数，这将删除当前的前导零，然后将其转换为字符串并反转.最后将其转换为整数以返回它.

Essentially I'm turning the integer into a string, reversing the string, turning it back into an integer---which removes the now leading zeros, turning it back into a string and reversing it; and finally turning it back into an integer to return it.

任何帮助将不胜感激.

推荐答案

只需使用您也可以在不将数字转换为字符串的情况下执行此操作，这应该会更快一些:

You could also do it without converting the number to a string, which should be slightly faster:

def remove_zeros(number):
    while number % 10 == 0:
        number //= 10
    return number

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