发送HTTP POST请求,使用SOAP org.apache.http行动 [英] Sending HTTP Post request with SOAP action using org.apache.http
问题描述
我试着写与SOAP动作的硬codeD HTTP POST请求,使用org.apache.http API。
我的问题是我没有找到一个方法来添加一个请求主体(在我的情况 - SOAP动作)。
我会很高兴的一些指导。
进口java.net.URI中;
进口org.apache.http.Htt presponse;
进口org.apache.http.client.HttpClient;
进口org.apache.http.client.methods.HttpPost;
进口org.apache.http.entity.StringEntity;
进口org.apache.http.impl.client.DefaultHttpClient;
进口org.apache.http.impl.client.RequestWrapper;
进口org.apache.http.protocol.HTTP;公共类HTT prequest
{
@燮pressWarnings(未使用)
公共HTT prequest()
{
尝试{
HttpClient的HttpClient的=新DefaultHttpClient();
绳体=DataDataData;
字符串bodyLength =新的整数(body.length())的toString()。
的System.out.println(bodyLength);
// StringEntity stringEntity =新StringEntity(体); URI URI =新的URI(SOMEURL参数1 = 1234&放大器;参数2 = ABCD);
HttpPost httpPost =新HttpPost(URI);
httpPost.addHeader(测试,Test_Value);// httpPost.setEntity(stringEntity); StringEntity实体=新StringEntity(身体,文/ XML,HTTP.DEFAULT_CONTENT_CHARSET);
httpPost.setEntity(实体); RequestWrapper此类RequestWrapper此类=新RequestWrapper此类(httpPost);
requestWrapper.setMethod(POST);
requestWrapper.setHeader(LuckyNumber,77);
requestWrapper.removeHeaders(主机);
requestWrapper.setHeader(主机,GOD_IS_A_DJ);
// requestWrapper.setHeader(内容长度,bodyLength);
HTT presponse响应= httpclient.execute(RequestWrapper此类);
}赶上(例外五){
e.printStackTrace();
}
}
}
将SOAPAction必须作为一个HTTP头参数传递 - 使用时,它不是HTTP体/负载的一部分
在这里寻找与Apache HttpClient的一个例子:的http://svn.apache.org/repos/asf/httpcomponents/oac.hc3x/trunk/src/examples/PostSOAP.java
I'm trying to write a hard-coded HTTP Post request with SOAP action, using the org.apache.http api. My problem is I didn't find a way to add a request body (in my case - SOAP action). I'll be glad for some guidance.
import java.net.URI;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.impl.client.RequestWrapper;
import org.apache.http.protocol.HTTP;
public class HTTPRequest
{
@SuppressWarnings("unused")
public HTTPRequest()
{
try {
HttpClient httpclient = new DefaultHttpClient();
String body="DataDataData";
String bodyLength=new Integer(body.length()).toString();
System.out.println(bodyLength);
// StringEntity stringEntity=new StringEntity(body);
URI uri=new URI("SOMEURL?Param1=1234&Param2=abcd");
HttpPost httpPost = new HttpPost(uri);
httpPost.addHeader("Test", "Test_Value");
// httpPost.setEntity(stringEntity);
StringEntity entity = new StringEntity(body, "text/xml",HTTP.DEFAULT_CONTENT_CHARSET);
httpPost.setEntity(entity);
RequestWrapper requestWrapper=new RequestWrapper(httpPost);
requestWrapper.setMethod("POST");
requestWrapper.setHeader("LuckyNumber", "77");
requestWrapper.removeHeaders("Host");
requestWrapper.setHeader("Host", "GOD_IS_A_DJ");
// requestWrapper.setHeader("Content-Length",bodyLength);
HttpResponse response = httpclient.execute(requestWrapper);
} catch (Exception e) {
e.printStackTrace();
}
}
}
The soapAction must passed as a http-header parameter - when used, it's not part of the http-body/payload.
Look here for an example with apache httpclient: http://svn.apache.org/repos/asf/httpcomponents/oac.hc3x/trunk/src/examples/PostSOAP.java
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