使用 org.apache.http 发送带有 SOAP 操作的 HTTP Post 请求 [英] Sending HTTP Post request with SOAP action using org.apache.http

问题描述

我正在尝试使用 org.apache.http api 编写带有 SOAP 操作的硬编码 HTTP Post 请求.我的问题是我没有找到添加请求正文的方法(在我的情况下 - SOAP 操作).我很乐意为您提供指导.

I'm trying to write a hard-coded HTTP Post request with SOAP action, using the org.apache.http api. My problem is I didn't find a way to add a request body (in my case - SOAP action). I'll be glad for some guidance.

import java.net.URI;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.impl.client.RequestWrapper;
import org.apache.http.protocol.HTTP;

public class HTTPRequest
{
    @SuppressWarnings("unused")
    public HTTPRequest()
    {
        try {
            HttpClient httpclient = new DefaultHttpClient();
            String body="DataDataData";
            String bodyLength=new Integer(body.length()).toString();
            System.out.println(bodyLength);
//          StringEntity stringEntity=new StringEntity(body);

            URI uri=new URI("SOMEURL?Param1=1234&Param2=abcd");
            HttpPost httpPost = new HttpPost(uri);
            httpPost.addHeader("Test", "Test_Value");

//          httpPost.setEntity(stringEntity);

            StringEntity entity = new StringEntity(body, "text/xml",HTTP.DEFAULT_CONTENT_CHARSET);
            httpPost.setEntity(entity);

            RequestWrapper requestWrapper=new RequestWrapper(httpPost);
            requestWrapper.setMethod("POST");
            requestWrapper.setHeader("LuckyNumber", "77");
            requestWrapper.removeHeaders("Host");
            requestWrapper.setHeader("Host", "GOD_IS_A_DJ");
//          requestWrapper.setHeader("Content-Length",bodyLength);          
            HttpResponse response = httpclient.execute(requestWrapper);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

推荐答案

soapAction 必须作为 http-header 参数传递 - 使用时，它不是 http-body/payload 的一部分.

The soapAction must passed as a http-header parameter - when used, it's not part of the http-body/payload.

在此处查看 apache httpclient 的示例:http://svn.apache.org/repos/asf/httpcomponents/oac.hc3x/trunk/src/examples/PostSOAP.java

Look here for an example with apache httpclient: http://svn.apache.org/repos/asf/httpcomponents/oac.hc3x/trunk/src/examples/PostSOAP.java

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