bash php沉默segfault [英] bash php silence segfault

问题描述

我需要阻止所有php输出， https://stackoverflow.com/a/617184/1695680 涵盖了如何总体上可以做到这一点，并且到目前为止，它仍然可以解决异常，语法错误等问题.

I need to prevent all php output, https://stackoverflow.com/a/617184/1695680 covers how to do this in general and for exception, errors, syntax errors so far it has worked, but.

php在pcre扩展中产生段错误: https://ilia.ws/archives/5_Top_10_ways_to_crash_PHP.html

php to produce a segfault in the pcre extension: https://ilia.ws/archives/5_Top_10_ways_to_crash_PHP.html

<?php
# prce-bug.php

preg_match('/(.(?!b))*/', str_repeat("a", 10000));

在我的测试中，这仍然输出:

In my testing, this still outputs:

user@host ~/crash-php $ php pcre-bug.php 
Segmentation fault (core dumped)

user@host ~/crash-php $ php pcre-bug.php  >/dev/null 2>&1
Segmentation fault (core dumped)

因此，即使使用shell输出重定向，输出也将到达我的终端.

So even with shell output redirection, output is getting to my terminal.

推荐答案

我发现使用新的sh shell实例将捕获系统报告的进程死亡，例如Segmentation Fault和Killed.

I found that using a new sh shell instance will capture system reported process deaths, like Segmentation Fault and Killed.

sh -c 'php pcre-bug.php' >/dev/null 2>&1

但是，输入参数不会传递给php，而是传递给与它们无关的sh实例.

However, input arguments do not go to php, but rather to the sh instance which does nothing with them.

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