如何在Swift中从两个结构数组中删除常见项目 [英] How to remove common items from two struct arrays in Swift

问题描述

在我的应用中，我有两个结构数组，我想从其中一个中删除常见项目.我的结构:

In my app I have two struct arrays and I want to remove common items from one of them. My struct:

struct PeopleSelectItem {
    var name = ""
    var id = ""
    var added = false
}

我的数组:

var people : [PeopleSelectItem] = []
var selectedPeople : [PeopleSelectItem] = []

我想从people数组中删除项目，如果它们存在于selectedPeople数组中(按ID比较).

I want to remove items from people array if they exist (compare by id) on selectedPeople array.

我尝试了几种数组过滤并将其转换为set的方法，但是它们都不起作用.我在这里可以做什么?

I tried several array filtering and converting to set but none of them worked. What can I do here?

谢谢！

推荐答案

• 获取selectedPeople中所有id的数组

  let selectedPeopleIDs = selectedPeople.map { $0.id }
  

• 过滤ID不在数组中的项目

• Filter the items whose id is not in the array

  let filteredPeople = people.filter { !selectedPeopleIDs.contains($0.id) }
  

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