Swift-错误:解开可选值时意外发现nil [英] Swift - Error: unexpectedly found nil while unwrapping an optional value

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本文介绍了Swift-错误:解开可选值时意外发现nil的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我一直在使用Swift制作应用程序,但是我在TableViewController类中始终遇到错误.我找不到任何方法来解决此问题,并不断出现此错误:

I have been making an app in Swift but I keep getting an error in my TableViewController class. I could not find any way to fix this and kept getting this error :

override func tableView(tableView: UITableView?, cellForRowAtIndexPath indexPath: NSIndexPath!) -> UITableViewCell!  {
        let cell : TextTableViewCell = tableView!.dequeueReusableCellWithIdentifier("Cell", forIndexPath : indexPath!) as TextTableViewCell

    let madan : PFObject = self.timeLineData.objectAtIndex(indexPath!.row) as PFObject

    cell.timestampLabel.alpha = 0
    cell.usernameLabel.alpha = 0
    cell.madanTextView.alpha = 0

    cell.madanTextView.text = madan.objectForKey("content") as String

    var dateFormatter : NSDateFormatter = NSDateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy HH:mm"
    cell.timestampLabel.text = dateFormatter.stringFromDate(madan.createdAt)

    var findSender : PFQuery = PFUser.query()
    findSender.whereKey("objectId", equalTo: madan.objectForKey("sender").objectId)
    var i = 1
    findSender.findObjectsInBackgroundWithBlock {
        (objects: [AnyObject]!, error: NSError!) -> Void in
        if !error {
            let user : PFUser = (objects as NSArray).lastObject as PFUser // Error here

            cell.usernameLabel.text = user.username 

            UIView.animateWithDuration(0.5, animations: {

                cell.timestampLabel.alpha = 1
                cell.usernameLabel.alpha = 1
                cell.madanTextView.alpha = 1

            })
        }
    }    
    return cell
}

我找不到任何解决方法.

I cannot find any way to fix this.

推荐答案

看起来objects好像又回到了nil.首先检查是否为零:

It looks as if objects is coming back as nil. First check for nil:

if !error {
    if let actualObjects = objects {
        let possibleUser = (actualObjects as NSArray).lastObject as? PFUser
        if let user = possibleUser {
            cell.usernameLabel.text = user.username
            // ...
        }
    }
}

注意:我将您的as更改为as?. lastObject已经返回了Optional,因此如果最后一个对象无法转换为PFUser,则最好继续执行.另外,由于lastObject可能返回nil,因此您还需要检查nil.

Note: I changed your as to as?. lastObject is already returning an Optional and so you might as well let the execution continue if the last object cannot be converted to PFUser. Also, because lastObject might return nil, you also need to check that for nil.

这篇关于Swift-错误:解开可选值时意外发现nil的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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