在Python中将.txt文件转换为图像 [英] Converting a .txt file to an image in Python
问题描述
我有一些代码可以将图像转换为ascii艺术图像. 当前，它将其输出为.txt文件，但该文件可以包含数十万个字符.如何将文件转换为.png文件等图像?
当前，它基于像素密度构建字符向量，然后将其写入.txt图像中.
如果我正确理解，您想要的图像看起来就像是有人在拍摄的ascii艺术的屏幕截图一样，就像在巨大的无限制文本编辑器中一样. /p>
我做过类似的事情，可以通过PILLOW以编程方式生成文本.这是从我的此代码修改而成的示例.希望这段代码可以帮助您和其他人避免我为了弄清楚如何使事情看起来合理而不得不做的事情.
这是下面代码的示例结果.
该代码是对链接库的直接修改，可以使用文本文件而不是字符串.
import PIL
import PIL.Image
import PIL.ImageFont
import PIL.ImageOps
import PIL.ImageDraw
PIXEL_ON = 0 # PIL color to use for "on"
PIXEL_OFF = 255 # PIL color to use for "off"
def main():
image = text_image('content.txt')
image.show()
image.save('content.png')
def text_image(text_path, font_path=None):
"""Convert text file to a grayscale image with black characters on a white background.
arguments:
text_path - the content of this file will be converted to an image
font_path - path to a font file (for example impact.ttf)
"""
grayscale = 'L'
# parse the file into lines
with open(text_path) as text_file: # can throw FileNotFoundError
lines = tuple(l.rstrip() for l in text_file.readlines())
# choose a font (you can see more detail in my library on github)
large_font = 20 # get better resolution with larger size
font_path = font_path or 'cour.ttf' # Courier New. works in windows. linux may need more explicit path
try:
font = PIL.ImageFont.truetype(font_path, size=large_font)
except IOError:
font = PIL.ImageFont.load_default()
print('Could not use chosen font. Using default.')
# make the background image based on the combination of font and lines
pt2px = lambda pt: int(round(pt * 96.0 / 72)) # convert points to pixels
max_width_line = max(lines, key=lambda s: font.getsize(s)[0])
# max height is adjusted down because it's too large visually for spacing
test_string = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
max_height = pt2px(font.getsize(test_string)[1])
max_width = pt2px(font.getsize(max_width_line)[0])
height = max_height * len(lines) # perfect or a little oversized
width = int(round(max_width + 40)) # a little oversized
image = PIL.Image.new(grayscale, (width, height), color=PIXEL_OFF)
draw = PIL.ImageDraw.Draw(image)
# draw each line of text
vertical_position = 5
horizontal_position = 5
line_spacing = int(round(max_height * 0.8)) # reduced spacing seems better
for line in lines:
draw.text((horizontal_position, vertical_position),
line, fill=PIXEL_ON, font=font)
vertical_position += line_spacing
# crop the text
c_box = PIL.ImageOps.invert(image).getbbox()
image = image.crop(c_box)
return image
if __name__ == '__main__':
main()
顺便说一句，所有这些代码可能都不应该填充在一个函数中，但是我认为对于示例代码而言，它变得更加简单.
I have some code that converts an image into an ascii art image. Currently it outputs it as a .txt file, but the file can have several hundred thousand characters. How can I convert the file to an image such as a .png file?
Currently it builds a character vector based on the pixel density, and then writes the vector into a .txt image.
If I understand correctly, you want an image that looks as if someone took a screenshot of the ascii art as it would look in a giant unlimited text editor.
I have done something similar to generate text programmatically with PILLOW. Here is an example modified from this code of mine. Hopefully this code will help you and others avoid the fiddling I had to do to figure out how to make things look reasonable.
Here is an example result made from the code below.
The code is a straightforward modification of the linked library to work with a text file instead of a string.
import PIL
import PIL.Image
import PIL.ImageFont
import PIL.ImageOps
import PIL.ImageDraw
PIXEL_ON = 0 # PIL color to use for "on"
PIXEL_OFF = 255 # PIL color to use for "off"
def main():
image = text_image('content.txt')
image.show()
image.save('content.png')
def text_image(text_path, font_path=None):
"""Convert text file to a grayscale image with black characters on a white background.
arguments:
text_path - the content of this file will be converted to an image
font_path - path to a font file (for example impact.ttf)
"""
grayscale = 'L'
# parse the file into lines
with open(text_path) as text_file: # can throw FileNotFoundError
lines = tuple(l.rstrip() for l in text_file.readlines())
# choose a font (you can see more detail in my library on github)
large_font = 20 # get better resolution with larger size
font_path = font_path or 'cour.ttf' # Courier New. works in windows. linux may need more explicit path
try:
font = PIL.ImageFont.truetype(font_path, size=large_font)
except IOError:
font = PIL.ImageFont.load_default()
print('Could not use chosen font. Using default.')
# make the background image based on the combination of font and lines
pt2px = lambda pt: int(round(pt * 96.0 / 72)) # convert points to pixels
max_width_line = max(lines, key=lambda s: font.getsize(s)[0])
# max height is adjusted down because it's too large visually for spacing
test_string = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
max_height = pt2px(font.getsize(test_string)[1])
max_width = pt2px(font.getsize(max_width_line)[0])
height = max_height * len(lines) # perfect or a little oversized
width = int(round(max_width + 40)) # a little oversized
image = PIL.Image.new(grayscale, (width, height), color=PIXEL_OFF)
draw = PIL.ImageDraw.Draw(image)
# draw each line of text
vertical_position = 5
horizontal_position = 5
line_spacing = int(round(max_height * 0.8)) # reduced spacing seems better
for line in lines:
draw.text((horizontal_position, vertical_position),
line, fill=PIXEL_ON, font=font)
vertical_position += line_spacing
# crop the text
c_box = PIL.ImageOps.invert(image).getbbox()
image = image.crop(c_box)
return image
if __name__ == '__main__':
main()
By the way, all that code should probably not be stuffed in one function, but I think it makes it more simple for example code.
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