string :: replace是否会使迭代器和引用无效? [英] Does string::replace invallidate iterators and references?

问题描述

您好，我已经搜索了迭代器并引用了类字符串的无效，但没有找到结果.

Hello I've searched for iterator and reference invalidation of class string but I didn't find a result.

我有此代码:

int main(){
    std::string s = "const char* manipulation in C++";
    auto beg = s.cbegin();
    auto& r = *s.begin();
    std::cout << s << std::endl;
    std::cout << "*beg: " << *beg << std::endl;
    std::cout << "r: " << r << std::endl;

    s.replace(beg, beg + 11, "string");
    std::cout << s << std::endl;
    std::cout << "*beg: " << *beg << std::endl;        
    std::cout << "r: " << r << std::endl;

}

输出:

const char* manipulation in C++
*beg: c
r: c
string manipulation in C++
*beg: s
r: s

它看起来不错，但我不知道它是否是未定义的行为.谢谢！

It looks good but I don't know whether it is undefined behavior or not. Thank you!

推荐答案

根据此参考:

与此对象相关的任何迭代器，指针和引用都可以是 无效.

Any iterators, pointers and references related to this object may be invalidated.

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