Python:itertools.product()的更快替代品? [英] Python: faster alternative for itertools.product()?

问题描述

我正在尝试查找长度= 22&的列表的所有可能组合.元素值= 1-9.

I'm trying to find all possible combinations of a list with length = 22 & element values = 1-9.

当我使用[i for i in itertools.product(range(1, 10), repeat=22)]时，Python崩溃. Python有更快的替代方法吗?

When I use [i for i in itertools.product(range(1, 10), repeat=22)], Python crashes. Does Python have a faster alternative?

推荐答案

每个人都评论过，请尝试直接使用生成器，而不要使用列表. 查找所有组合尚不清楚.如果需要打印它们，请执行以下操作:

As everyone commented, try using the generator directly instead of using a list. finding all combinations is unclear. If you need to print them, do this:

for i in itertools.product(range(1, 10), repeat=22):
    ... #Don't actually print, that may block your computer for a long time.

如果您需要对这些值做些事情，然后告诉我们您需要什么.

if you need to do something on those values, then tell us what you need.

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