在使用jasmine.createSpyObj实用程序构建SpyObj时声明吸气剂属性? [英] Declaring getter property when building SpyObj using jasmine.createSpyObj utility?

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问题描述

让我说一堂课

class MyRealClass {
  get propOne() { return stuffFromTheServer; }
}

在测试时,我想实现此功能:

When testing, I want to achieve this functionality:

const mockClass = {
  get propOne() { return someStuff; }
}

jasmine.spyOnProperty(mockClass, 'propOne', 'get');

通过做这样的事情...

By doing something like this...

const spy = jasmine.createSpyObj('mockClass', [
  {methodName: 'propOne', accessType: 'get'}
]);

换句话说,我想使用jasmine.createSpyObj构建一个SpyObj<MyRealClass>并将getter属性声明为methodName数组中的方法(第二个参数是createSpyObj()方法.

In other words, I want to build a SpyObj<MyRealClass> using the jasmine.createSpyObj and declare the getter properties as methods in the methodName array (the second parameter the the createSpyObj() method.

这可能吗?

推荐答案

通过此代码,我做到了令人惊讶的简单:

I did it surprisingly simple by this code:

const routerMock = jasmine.createSpyObj(['events']);
routerMock.events = of(new NavigationEnd(0, 'url1', 'url2'));

const serviceToTest = new SomeService(routerMock);

这篇关于在使用jasmine.createSpyObj实用程序构建SpyObj时声明吸气剂属性?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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